Project Euler Problem 6

Project Euler R

The sum of the squares of the first ten natural numbers is, 1^(2) + 2^(2) + ... + 10^(2) = 385

The square of the sum of the first ten natural numbers is, (1 + 2 + ... + 10)^(2) = 55^(2) = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

ヘボいオレでも流石に簡単すぎる．．．

fr <- function(x){
      x^2
      }
sum(1:100)^2 - sum(fr(1:100))